use_of_void_result
This expression has a type of 'void' so its value can't be used.
Description
#The analyzer produces this diagnostic when it finds an expression whose
type is void
, and the expression is used in a place where a value is
expected, such as before a member access or on the right-hand side of an
assignment.
Example
#The following code produces this diagnostic because f
doesn't produce an
object on which toString
can be invoked:
dart
void f() {}
void g() {
f().toString();
}
Common fixes
#除非另有说明,文档之所提及适用于 Dart 3.7.3 版本,本页面最后更新时间: 2025-05-08。 查看文档源码 或者 报告页面问题。