break_label_on_switch_member

A break label resolves to the 'case' or 'default' statement.

The analyzer produces this diagnostic when a break in a case clause inside a switch statement has a label that is associated with another case clause.

The following code produces this diagnostic because the label l is associated with the case clause for 0:

void f(int i) {
  switch (i) {
    l: case 0:
      break;
    case 1:
      break l;
  }
}

If the intent is to transfer control to the statement after the switch, then remove the label from the break statement:

void f(int i) {
  switch (i) {
    case 0:
      break;
    case 1:
      break;
  }
}

If the intent is to transfer control to a different case block, then use continue rather than break:

void f(int i) {
  switch (i) {
    l: case 0:
      break;
    case 1:
      continue l;
  }
}

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