unnecessary_string_escapes
Unnecessary escape in string literal.
Description
#The analyzer produces this diagnostic when characters in a string are escaped when escaping them is unnecessary.
Example
#The following code produces this diagnostic because single quotes don't need to be escaped inside strings delimited by double quotes:
dart
var s = "Don\'t use a backslash here.";
Common fixes
#Remove the unnecessary backslashes:
dart
var s = "Don't use a backslash here.";
除非另有说明,文档之所提及适用于 Dart 3.7.3 版本,本页面最后更新时间: 2025-05-08。 查看文档源码 或者 报告页面问题。