non_type_as_type_argument
The name '{0}' isn't a type, so it can't be used as a type argument.
Description
#The analyzer produces this diagnostic when an identifier that isn't a type is used as a type argument.
Example
#The following code produces this diagnostic because x
is a variable, not
a type:
dart
var x = 0;
List<x> xList = [];
Common fixes
#Change the type argument to be a type:
dart
var x = 0;
List<int> xList = [];
除非另有说明,文档之所提及适用于 Dart 3.7.3 版本,本页面最后更新时间: 2025-05-08。 查看文档源码 或者 报告页面问题。