no_raw_types

The generic type '{0}' should have explicit type arguments but doesn't.

The analyzer produces this diagnostic when a generic type is used without explicit type arguments, meaning it is a raw type.

The following code produces this diagnostic because the generic class C is used without a type argument:

class C<T> {}
C c = C<int>();

Provide explicit type arguments:

class C<T> {}
C<int> c = C<int>();